G(x)=-0.01x^2+x+68

Solution for G(x)=-0.01x^2+x+68 equation:

(G)=-0.01G^2+G+68

We move all terms to the left:

(G)-(-0.01G^2+G+68)=0

We get rid of parentheses

0.01G^2-G+G-68=0

We add all the numbers together, and all the variables

0.01G^2-68=0

a = 0.01; b = 0; c = -68;
Δ = b2-4ac
Δ = 02-4·0.01·(-68)
Δ = 2.72
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{2.72}}{2*0.01}=\frac{0-\sqrt{2.72}}{0.02}
=-\frac{\sqrt{}}{0.02}
$
$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{2.72}}{2*0.01}=\frac{0+\sqrt{2.72}}{0.02}
=\frac{\sqrt{}}{0.02}
$